What is the solution to the equation below? Round your answer to twodecimal places.eX = 7.9
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Solution
For this case we have the following equation:
[tex]e^x=7.9[/tex]For this case we can apply natural log in both sides and we got:
[tex]\ln (x)=\ln (7.9)=2.07[/tex]and then the solution would be:
D. x =2.07