6. What is the equation in standard form of the line that passes through the point 2 ? (10,-3) and has a slope of 5
![6 What is the equation in standard form of the line that passes through the point 2 103 and has a slope of 5 class=](https://us-static.z-dn.net/files/df3/c17fb58f4a7b63850aa535c27dc562b0.png)
The standard form of equation of line is :
[tex]y=m(x-x_1)+y_1[/tex]In the given question, we have coordinates : (10,-3) and slope m = 2/5
[tex]\begin{gathered} y=m(x-x_1)+y_1 \\ y=\frac{2}{5}(x-10)+(-3) \\ y=\frac{2}{5}x-\frac{2}{5}(-10)+(-3) \\ y=\frac{2}{5}x-2(-2)+(-3) \\ y=\frac{2}{5}x-4-3 \\ y=\frac{2}{5}x-7 \\ y+7=\frac{2}{5}x \\ 5y+35=2x \\ 2x\text{ -5y =35} \end{gathered}[/tex]The equation of line is 2x - 5y = 35
Anwer : C) 2x - 5y = 35