Respuesta :

Solution:

Given:

A circle with the sector details;

[tex]\begin{gathered} r=19\text{ }in \\ \theta=135^0 \end{gathered}[/tex]

The area of a sector is given by;

[tex]\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{135}{360}\times\pi\times19^2 \\ A=\frac{1083\pi}{8}\text{ }in^2 \end{gathered}[/tex]

Therefore, the area of the sector is;

[tex]\frac{1083\pi}{8}\text{ }in^2[/tex]

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