can you show me like on a same graph like mine
![can you show me like on a same graph like mine class=](https://us-static.z-dn.net/files/dc2/ea6ca7aa937ad21fa0e90514e613f97a.png)
Given the general quadratic equation:
[tex]ax^2+bx+c=0[/tex]The general solution of the quadratic equation is given by the expression:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]From the problem, we have the quadratic equation:
[tex]3x{}^2+2x-225=0[/tex]Identifying the coefficients:
[tex]\begin{gathered} a=3 \\ b=2 \\ c=-225 \end{gathered}[/tex]Then, using the general solution formula:
[tex]\begin{gathered} x=\frac{-2\pm\sqrt{4+2700}}{6}=\frac{-2\pm52}{6} \\ \\ \Rightarrow x_1=\frac{25}{3} \\ \\ \Rightarrow x_2=-9 \end{gathered}[/tex]And the solutions on the number line are: