Question

Zeros 4 and -3iI already asked for the last question, but I’m confused for the i

Answer 1

Given:

The zeros of the polynomial are 4 and 3i.

Required:

To find the polynomial of the function.

Explanation:

Here

$\begin{gathered} x=4 \\ x=-3i \end{gathered}$$\begin{gathered} x-4=0\text{ and} \\ x+3i=0 \end{gathered}$

Therefore

$\begin{gathered} (x-4)(x+3i)=0 \\ \\ x^2-4x-3ix-12i=0 \\ \\ x^2-(4+3i)x-12i=0 \end{gathered}$

Final Answer:

$x^2-(4+3i)x-12i=0$