Find the starting value and the base for the exponential function f(x)=kb^x that passes through the two points:(0,3) and (2,12).The starting value k is: AnswerThe base b is: Answer
![Find the starting value and the base for the exponential function fxkbx that passes through the two points03 and 212The starting value k is AnswerThe base b is class=](https://us-static.z-dn.net/files/da6/dbca7445228c36f3d4b45422a8f2470b.png)
The exponential equation given is,
[tex]f(x)=kb^x[/tex]Given the points
[tex](0,3)\text{ and (2,12)}[/tex]Therefore, the values for k and b will be resolved graphically.
Let us now plot the graph using a graphical calculator
From the graph,
[tex]\begin{gathered} y_1=f(x) \\ a=k=3 \\ b=2 \end{gathered}[/tex]Final answers
[tex]\begin{gathered} k=3 \\ b=2 \end{gathered}[/tex]