Question

in the right triangle ABC, if m < C = 90 and sun A = 3/5, cos B is

Answer 1

Given a right angle triangle ABC:

$\begin{gathered} m\angle C=90 \\ \sin A=\frac{3}{5} \end{gathered}$

As the measure of angle C = 90

so, the sum of the angles A and B = 90

So, angles A and B are complementary angles

so,

$\begin{gathered} \sin A=\cos B \\ \\ \cos B=\sin A=\frac{3}{5} \end{gathered}$

so, the answer will be cos B = 3/5