Question

solve the polynomial in standard form1) y=(x-3)^2-3(x-4)

Answer 1

$y=\mleft(x-3\mright)^2-3\mleft(x-4\mright)$$\begin{gathered} y=x^2-6x+9-3x+12 \\ \end{gathered}$

we reduce the equal terms and we obtain the answer is

$y=x^2-9x+21$