Answer:
It is 0.696% for Part A, and 0.634% for Part B
Male students are more represented in Part A.
Explanation:
Given that there are 19100 students.
For Part A, the percentage of male students is part A is:
[tex]\begin{gathered} \frac{\text{Sum of male students in part A}}{\text{Total male students}} \\ \\ =\frac{133}{19100}\times100 \\ \\ =0.696 \end{gathered}[/tex]
For Part A, the percentage of male students is part B is:
[tex]\begin{gathered} \frac{121}{19100}\times100 \\ \\ =0.634 \end{gathered}[/tex]
