how do I find the central angle for turn b?
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We will to use the formula to a sector areaa, which is given for:
[tex]A=r^2\theta/2[/tex]Where r is the radius and θ is the central angle.
We can rewrite the formula to obtain the central angle like this:
[tex]\theta=\frac{2A}{r^2}[/tex]We replace with the values of the track:
[tex]\theta=\frac{2\ast51\pi}{20\ast3^2}=\frac{17\pi}{30}[/tex]Then we change radians to degrees:
[tex]\frac{17\pi}{30}\ast\frac{180}{\pi}=102\text{ \degree}[/tex]Then the correct answer is 102°.