A lamp draws a current of 0.50 A when it is connected to a 120 V source. What is the resistance of the lamp?1) 4.17 10-2 ω2) 60 ω3) 2.4 102 ω4) 24 102 ω
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Given data:
* The voltage of the given source is,
[tex]V=120\text{ Volts}[/tex]* The current through the lamp is,
[tex]I=0.5\text{ A}[/tex]Solution:
By the Ohm's law,
[tex]V=IR[/tex]where R is the resistance of the lamp,
Substituting the known values,
[tex]\begin{gathered} 120=0.5\times R \\ R=\frac{120}{0.5} \\ R=240\text{ }\Omega \\ R=2.4\times10^2\text{ }\Omega \end{gathered}[/tex]Thus, 3rd option is the correct answer.