In the diagram below, quadrilateral ABCD is inscribed in circle P.What is m< DCB?
![In the diagram below quadrilateral ABCD is inscribed in circle PWhat is mlt DCB class=](https://us-static.z-dn.net/files/d74/db97366bc634544abb48db5961e69cd3.png)
ANSWER
A) 70º
EXPLANATION
In quadrilaterals inscribed in a circle, opposite angles are supplementary - their measures add up 180º. Therefore:
[tex]\begin{gathered} m\angle DAB+m\angle DCB=180º \\ 110º+m\angle DCB=180º \\ m\angle DCB=180º-110º \\ m\angle DCB=70º \end{gathered}[/tex]