Question

Suppose that a is an angle with seca alpha = - 11/10 and a is not in the third quadrant. Compute the exact value of sina. You do not have to rationalize the denominatorSin a =

Answer 1

Answer:$\sin\alpha=0.41628$

Explanation:

Given that

$sec\text{ }\alpha=-\frac{11}{10}$

$\alpha=sec^{-1}(-\frac{11}{10})=155.4^o$

Now

$\sin\alpha=\sin155.4=0.41628$