Question

What is the probability of meeting at least one person with the flu in twelve random encounters on campus when the infection rate is 8%

Answer 1

Solution:

$p(x)=(0.08)^x(0.92)^{12-x}$

The probability of at least one person is;

$\begin{gathered} 1-p(0)=1-(0.08)^0(0.92)^{12-0} \\ \\ =0.6323 \end{gathered}$