y = x/3 (option 3)
Explanation:
To determine the equation that represents the function, first we will find the slope.
points (-9, -3) and (-12, -4)
[tex]\begin{gathered} \text{slope = }m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \end{gathered}[/tex][tex]\begin{gathered} m\text{ = }\frac{-4_{}-(-3)_{}}{-12_{}-(-9_{})}\text{ = }\frac{-4+3}{-12+9} \\ m\text{ =}\frac{-1}{-3}\text{ = 1/3} \end{gathered}[/tex]Then we will insert the value of the slope in the equation of a straight line:
y = mx + c
y = 1/3 (x) +c
where c = 0
y = x/3 (option 3)