Question

If f(x) = x^2 on the domain [-2, 2] then f^-1

Answer 1

SOLUTION:

Step 1 :

In this question, we are given that:

$\begin{gathered} \text{If f ( x ) = x }^2\text{ on the domain of }\lbrack\text{ -2 , 2}\rbrack,^{} \\ \text{Then f }^{-1}\colon \end{gathered}$

Step 2 :

$\begin{gathered} f(x)=x^2 \\ \text{Let y = f( x )} \\ y=x^2 \\ \text{Then we square - root both sides, we have that:} \end{gathered}$$\begin{gathered} x\text{ = }\sqrt[]{y} \\ \text{f }^{-1\text{ }}\text{ ( x ) = }\sqrt[]{\text{ x }}\text{ ( OPTION D )} \end{gathered}$