Question

Find the sine of each acute angle in the triangle below. Select all that apply:- 40/41- 41/9- 41/40- 9/40- 9/41

Answer 1

The sine relation is given by the length of the opposite leg to the angle over the length of the hypotenuse.

Using the angle between the sides 9 and 41, we have:

$\sin (\theta_1)=\frac{40}{41}$

Using the angle between 40 and 41, we have:

$\sin (\theta_2)=\frac{9}{41}$

Therefore the correct options are the first and fifth ones.