Question

A jar contains 8 white, 10 blue, and 18 red marbles. If one marble is drawn at random from the jar, find theprobability that:

Answer 1

To solve this problem, you can use the following formula:

$P(A)=\frac{outcome\text{ in A}}{total\text{ number of outcomes}}.$

Now, for all the problems, the total number of outcomes is:

$8+10+18=36.$

Now, there are 8 white marbles and 10 blue marbles, therefore:

$P(white\text{ or blue\rparen= }\frac{8+10}{36}=\frac{18}{36}=\frac{1}{2}.$

Analogously:

$P(white\text{ or red\rparen=}\frac{8+18}{36}=\frac{26}{36}=\frac{13}{18}.$$P(blue\text{ or red\rparen=}\frac{10+18}{36}=\frac{7}{9}.$

Answer:

1.-

$\frac{1}{2}.$

2.-

$\frac{13}{18}.$

3.-

$\frac{7}{9}.$