Question

Differentiate. f(x) = (4x2 - 8) - (1 + 4x3) f'(x) = 32x(4x2 - 8) 3 - 12x2(1 + 4x3,4 f'(x) = 32x(4x2 - 8) 3 - 60x?(1 + 4x3,4 f'(x) = (32x-8)(4x2 - 8)3 - (1 + 60x?)(1 + 4x334 f'(x) = 4(4x2 - 8) 3 - 5(1 +4x3)4

Answer 1

we have

f(x)=(4x2-8)^4-(1+4x^3)^5

so

f'(x)=4(4x^2-8)^3(8x)-5(1+4x^3)^4(12x^2)

f'(x)=32x(4x^2-8)-60x^2(1+4x^3)^4