Question

A car dealership decides to select a month at random for its annual sale find the probability that it will be July or October. Show all your work.

Answer 1

Answer:

1/6

Explanation:

The total number of months in a year = 12

$\begin{gathered} P(\text{July)}=\frac{1}{12} \\ P(\text{October)}=\frac{1}{12} \end{gathered}$

Therefore, the probability that it will be July or October:

$\begin{gathered} P(\text{July or October)=}P(\text{July)}+P(\text{October)} \\ =\frac{1}{12}+\frac{1}{12} \\ =\frac{2}{12} \\ =\frac{1}{6} \end{gathered}$

The required probability is 1/6.

Note:

• Use addition for OR

,

• Use multiplication for AND