AC = BD, mẠC = (5x + 5), mBC = (x + 16)® and mBD = (4x + 27).What is mBC?22°48°D11538°А
![AC BD mẠC 5x 5 mBC x 16 and mBD 4x 27What is mBC2248D11538А class=](https://us-static.z-dn.net/files/d87/bc08ea78a22007314ee7e208eb077dc0.png)
We are given two chords of equal length, this means that the arc they form are equal, this means:
[tex]\text{mAC}=\text{mBD}[/tex]Replacing the expressions for each arc we get:
[tex]5x+5=4x+27[/tex]From this expression we can solve for "x" first by subtracting "4x" to both sides:
[tex]5x-4x+5=27[/tex]Now we subtract 5 to both sides:
[tex]5x-4x=27-5[/tex]Now we add like terms:
[tex]x=22[/tex]Now we replace this value of "x" in the expression for arc BC-:
[tex]\text{mBC}=x+16[/tex]Replacing the value of "x":
[tex]\begin{gathered} \text{mBC}=22+16 \\ \text{mBC}=38 \end{gathered}[/tex]