Question

In the circle below BD = 172° and ACFind m/BXD.

Answer 1

Given:

$\begin{gathered} \hat{BD}=172\degree \\ \hat{AC}=56\degree \end{gathered}$

To determine the m$m\angle BXD=\frac{1}{2}(\hat{BD}+\hat{AC})$We plug in what we know:

$\begin{gathered} \begin{equation*} m\angle BXD=\frac{1}{2}(\hat{BD}+\hat{AC}) \end{equation*} \\ m\angle BXD=\frac{1}{2}(172+56) \\ Calculate \\ m\angle BXD=114\degree \end{gathered}$

Therefore, the answer is:

$\begin{equation*} 114\degree \end{equation*}$