Answer:
[tex]Mg_{(aq)}^{+2}+2OH_{(aq)}^-\operatorname{\rightarrow}Mg(OH)_{2(s)}.[/tex]Explanation:
Remember that a net ionic equation is the chemical equation that shows only those elements, compounds, and ions that are directly involved in the chemical reaction.
First, let's state the balanced chemical equation:
[tex]MgCl_2+2NaOH\rightarrow2NaCl+Mg(OH)_2.[/tex]To do the net ionic equation, we just have to 'separate' each ion of each reactant and those ones in the product that don't bond to the OH, like this:
[tex](Mg^{2+}+2Cl^-)+(2Na^++2OH^-)\rightarrow(2Na^++2Cl^-)+Mg(OH)_2.[/tex]The final step is to 'cancel' the ions that are repeated such as Cl (-) and Na (+), the net ionic equation would be with their respective phases:
[tex]Mg_{(aq)}^{2+}+2OH_{(aq)}^-\rightarrow Mg(OH)_{2(s)}.[/tex]