Question

The speed of a wave during a tsunami can be calculated vith the formula 3 - 1981d wheres represents speed in meters per second, d represents the depth of the water in meters wherethe disturbance (for example earthquake) takes place, and 981 m/s? is the acceleration due togravity. If the speed of the wave is 150 m/s, what is the approximate depth of the water wherethe disturbance took place?O 1.2 metersO 2,294 metersO 38 metersO 220,725 meters

Answer 1

Answer:

The approximate depth of the water where the disturbance takes place is;

$2,294\text{ m}$

Explanation:

Given the expression;

$s=\sqrt[]{9.81d}$

where; s equals the speed in meters per second and d represents the depth of the water in meters.

Given that the speed of the wave is 150 m/s

$s=150\text{ m/s}$

To solve for the depth d, let us make d the subject of formula in the given expression;

$\begin{gathered} s=\sqrt[]{9.81d} \\ s^2=9.81d \\ d=\frac{s^2}{9.81} \end{gathered}$

substituting the value of s;

$\begin{gathered} d=\frac{150^2}{9.81} \\ d=2,293.57798\text{ m} \\ d=2,294\text{ m} \end{gathered}$

Therefore, the approximate depth of the water where the disturbance takes place is;

$2,294\text{ m}$