Find the area the sector.arc circle 9A. 275π/6 m²B. 175π/2 m²C. 18π m²D. 5π/3 m²
![Find the area the sectorarc circle 9A 275π6 mB 175π2 mC 18π mD 5π3 m class=](https://us-static.z-dn.net/files/df5/949f378084a44514524dc7b12c443342.png)
Solution:
The area of a sector is expressed as
[tex]\begin{gathered} area=\frac{\theta}{360}\times\pi r^2 \\ where \\ \theta\Rightarrow angle\text{ subtended by the sector} \\ r\Rightarrow radius\text{ of the circle} \end{gathered}[/tex]Given:
we see that
[tex]\begin{gathered} \theta=165\degree \\ r=10\text{ m} \end{gathered}[/tex]By substitution, we have
[tex]\begin{gathered} area=\frac{165}{360}\times\pi\times10\times10 \\ =\frac{275\pi}{6}\text{ m}^2 \end{gathered}[/tex]Hence, the area of the sector is evaluated to be
[tex]\frac{275\pi}{6}\text{ m}^2[/tex]The correct option is A