Given:
A rectangular yard measuring 29 ft by 50 ft is bordered by a fence.
The area of the rectangle is given as,
[tex]\begin{gathered} A_R=\text{Length}\times Width \\ A_R=50\times29 \\ A_R=1450 \end{gathered}[/tex]The walkway is 3 ft wide. Then overall dimensions are reduce by 6 ft
The area inside the walkway is,
[tex]\begin{gathered} A_W=\mleft(50-2\cdot3\mright)\times(29-2\cdot3) \\ A_W=44\times\: 23 \\ A_W=1012 \end{gathered}[/tex]So, the area of the walk is,
[tex]\begin{gathered} A=A_R-A_W \\ A=1450-1012 \\ A=438\text{ square ft} \end{gathered}[/tex]Answer: 438 square ft.