Question

I know that AC and DB intersect at point E what would be the 3 pairs of angles though? More explanation

Answer 1

Solution;

From your drawing;

$m\angle ADE=m\angle BCE(angles\text{ in the same segment are equal})$$m\angle DAE=m\angle CBE(angles\text{ in the same segment are equal})$$m\angle AED=m\angle BEC(vertically\text{ opposite angles are equal})$