Let d represent the number of days Andrew can afford to rent while staying within his budget.
Let m represent the number of miles driven
We were told that the rental car company charges $30 per day to rent a car and $0.12 for every mile driven.The cost for d days would be $30d. The total cost for d days would be
0.12m + 30d
Given that he has at most $150 to spend, it means that the amount he needs to spend is less than or equal to $150
The inequality representing this scenario would be
[tex]\begin{gathered} 0.12m\text{ + 30d }\leq\text{ 150} \\ Given\text{ that m = 350, it becomes} \\ 0.12\text{ }\times350\text{ + 30d}\leq150 \\ 42\text{ + 30d }\leq150 \\ 30d\text{ }\leq150\text{ - 42} \\ 30d\text{ }\leq108 \\ d\text{ }\leq\text{ }\frac{108}{30} \\ d\text{ }\leq3.6 \end{gathered}[/tex]This means that the number of days is 3 because it cannot be a fraction. It is not up to 4 days