Question

In ∆ NOP , the measure of

Answer 1

We have six trigonometric ratios that can be applied to right triangles, that is, the triangles that have one angle equal to 90.

Before finding these ratios, we need to have a reference angle. In this case, the reference angle is Then, we have that the secant of an angle (in a right triangle) is given by:

$\sec (\theta)=\frac{hyp}{adj}$

That is, the secant is the ratio of the hypotenuse over the adjacent side of the angle. In this case, the angle is $\text{sec(}\angle N)=\frac{hyp}{adj}=\frac{41}{9}\Rightarrow\sec (\angle N)=\frac{41}{9}$Therefore, the secant of the angle N is represented by the ratio 41/9.