Question

14) A brother and sister try to communicate with a string tied between two tin cans. If the string is 7.6 m long, has a mass of 29 g, and is pulled taut with a tension of 18 N, how much time does it take for a wave to travel from one end of the string to the other?

Answer 1

Given data:

* The value of mass given is 29 g.

* The length of the string is 7.6 m.

* The tension on the string is 18 N.

Solution:

The time taken by the wave to travel through the string in terms of length, mass and tension is,

$t=\sqrt[]{\frac{ml}{T}}$

where m is the mass, l is the length and T is the tension in the string,

Substituting the known values,

$\begin{gathered} t=\sqrt[]{\frac{29\times10^{-3}\times7.6}{18}} \\ t=\sqrt[]{12.2\times10^{-3}} \\ t=\sqrt[]{0.0122} \\ t=0.11\text{ s} \end{gathered}$

Thus, the time taken by the wave to travel through the string is 0.11 s.