Question

b. Based on the data, estimate the probability that a randomly selected student from this class has three or more siblings. Number of Siblings 0 1 2 3 5 6 Count 8 13 12 3 1

Answer 1

In class total nmber of students is n(T) = 38.

The number of students with three or more than three siblings are

$\begin{gathered} n(\ge3)=3+1+0+1 \\ =5 \end{gathered}$

Determine the probability for the students with three or more than three siblings.

$\begin{gathered} P(\ge3)=\frac{n(\ge3)}{n(T)} \\ =\frac{5}{38} \\ =0.13157 \\ \approx0.132 \end{gathered}$

Thus answer is 5/38 or 0.132.