Respuesta :

Just use unit analysis, but you'll have to balance the equation first
3H2-> 2NH3 (Other products and reactants omitted)
3.64 g/ 2 (g/mol) * 2/3 * 17= 20.6 g of NH3

The number of grams of [tex]NH_3[/tex] that could be produced is 20.6g.

Given that,

  • There are 3.64g of [tex]H_2[/tex].
  • There is the chemical equation of [tex]N_2(g) +3H_2(g) \rightarrow 2NH_3 (g)[/tex].

Based on the above information, the calculation is as follows:

N2(g) +3H2(g)-> 2NH3 (g)

28g     6g             34g

Now

[tex]6gH_2 \rightarrow 34g NH_3[/tex]

So for 3.64g should be

[tex]= 34\times 3.6\div6[/tex]

= 20.6g

Therefore we can conclude that the number of grams of [tex]NH_3[/tex] that could be produced is 20.6g.

Learn more: brainly.com/question/943897