Question

How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?

Answer 1

The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J

Answer 2

Answer: The amount of heat required is 8625.4 J

Explanation:

To calculate the heat required, we use the equation:

$q=mc\Delta T$

where,

q = heat required = ?

m = mass of aluminium = 125 g

c = specific heat capacity of aluminium = 0.902 J/g.°C

$\Delta T$ = change in temperature = $T_2-T_1=95.5-19=76.5^oC$

Putting values in above equation, we get:

$q=125g\times 0.902J/g.^oC\times 76.5^oC\\\\\q=8625.4J$

Hence, the amount of heat required is 8625.4 J