Question

. If 250 mL of a 0.50 M NaCl solution is diluted to 840 mL, what is the molarity of the resulting solution?

Answer 1

M= mol/L
0.5M*0.25L= 0.125 moles
0.125 moles/0.840L =0.15M

Answer 2

Explanation:

The given data is as follows.

  $M_{1}$ = 0.50 M,                $V_{1}$ = 250 mL

  $M_{1}$ = ? ,                         $V_{1}$ = 840 mL

Therefore, calculate the molarity using the relation as follows.

               $M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

                  0.50 M × 250 mL = $M_{2}$ × 840 mL

                 $M_{2} = \frac{0.50 M \times 250 mL}{840 mL}$

                                   = 0.148 M

                                   = 0.15 M (approximately)

Thus, we can conclude that the molarity of the resulting solution is 0.15 M.