Question

27.What is the logarithmic form of the equation e2x ≈ 1732?

ln 1732 = 2x
log2x1732 = e
2 logxe = 1732
ln 2x = 1732

Answer 1

To get rid of exponential, you need to put ln on the other side.

So, to get 2x you need to write ln 1732

Answer is the first one.

Answer 2

Answer:

Logarithm form of $e^{2x}=1732$ is $2x=\ln 1732$

Step-by-step explanation:

Given equation $e^{2x}=1732$

We need to write given exponential form into logarithm

using log property to write in logarithm

$a^m=x$

$m\ln a=\ln x$

$e^{2x}=1732$

Apply ln both sides

$2x\ln e=\ln 1732$

$2x=\ln 1732$                       ∴ln e = 1

Thus, Logarithm form of $e^{2x}=1732$ is $2x=\ln 1732$