Question

Determine the exact value of 0 in the following equation if 0 < a < 27.--4cos 0 + 7 = -2V3+7

Answer 1

Given:

The trigonometric equation is,

$-4\cos \theta+7=-2\sqrt[]{3}+7$

Explanation:

Simplify the equation for angle theta.

$\begin{gathered} -4\cos \theta+7=-2\sqrt[]{3}+7 \\ -4\cos \theta=-2\sqrt[]{3} \\ \cos \theta=\frac{-2\sqrt[]{3}}{-4} \\ \theta=\cos ^{-1}(\frac{\sqrt[]{3}}{2}) \\ =\frac{\pi}{6},\frac{11\pi}{6} \end{gathered}$

So answer is,

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