Given the information, we have the following:
Now, since AC=15, we have the following expression:
[tex]\begin{gathered} AB+BC=AC \\ \Rightarrow(x+14)+(x+13)=15 \end{gathered}[/tex]Solving for x we get:
[tex]\begin{gathered} (x+14)+(x+13)=15 \\ \Rightarrow2x=15-14-13=-12 \\ \Rightarrow2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]Therefore, x=-6