Question

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml at a constant pressure of 2.0 atm. calculate the work associated with this process

Answer 1

5 ml = 0,05l
Work = Pressure * (Volume difference)
W= 2 * (V2 - V1)
W= 2 * (4,95)

Answer 2

Answer:

The work is 9.99J.

Explanation:

The work associated with a process is given by the following formula:

$W = P*\Delta$

In which W is the work, P is the pressure and $\Delta$ is the difference of volume.

In this problem, we have that:

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml. Each ml has 0.001l. So the volume of the ideal gas is decreased from 5.0l to 0.005l. So

$\Delta = 4.995$.

Constant pressure of 2.0 atm. So $P = 2$.

$W = P*\Delta$

$W = 2*4.995$

$W = 9.99$

The work is 9.99J.