a synthetic fiber used in manufacturing carpet has a tensile strength that is normally distributed with a mean 75.5 psi and standard deviation 3.5 psi. find the probability that a random sample of n

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The sample tensile strength of fiber specimens will be greater than 75.75 psi in 43.25 percent of cases.

What is meant by Z-score?

Z-score: Z-score indicates how much a given value differs from the standard deviation. The Z-score, or standard score, is the number of standard deviations a given data point lies above or below mean. Standard deviation is essentially a reflection of the amount of variability within a given data set.

given that a synthetic fiber used in manufacturing carpet has a tensile strength that is normally distributed with a mean 75.5 psi and standard deviation 3.5 psi

z = (raw score - mean) / (sample standard deviation - standard deviation)

n = 6; mean=75.5 psi; standard deviation=3.5 psi.

For (greater than) > 75.75,

z = (75.75 - 75.5) / (3.5 ÷√6) = 0.17

P(z > 0.17) = 1 - P(z < 0.17) = 1 - 0.5675 = 43.25%

The sample tensile strength of fiber specimens will be greater than 75.75 psi in 43.25 percent of cases.

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