Question

To what volume should 24 mL of a 6.00 M sulfuric acid solution be diluted in order to obtain a final solution that is 1.50 M?

Answer 1

They ask us to make a solution starting from a solution with a higher concentration, to find the final volume we will apply the following relationship of concentration and volume:

$C_1V_1=C_2V_2$

Where,

C1 is the initial concetration, 6.00M

V1 is the initial volume, 24mL

C2 is the final concentration, 1.50M

V2 is the final volumen, unknown

We clear V2 and replace the known data:

$V_2=\frac{C_1V_1}{C_2}$$\begin{gathered} V_2=\frac{6.00M\times24mL}{1.50M} \\ V_2=96mL \end{gathered}$

The solution has to be diluted until a volume equal to 96mL

Answer: 96mL