The first step is to determine how many moles of each ion are there in one mole of (NH4)2CO3.
In one mole of (NH4)2CO3, there are 2 moles of NH4 + and 1 mole of CO3 2-.
Find the number of moles that are present in 36.5mL of solution by multiplying this volume times the concentration of the solution. First convert the mililiters to liters (1L=1000mL):
[tex]\begin{gathered} 36.5mL\cdot\frac{L}{1000mL}=0.0365L \\ 0.0365L\cdot\frac{0.595mol}{L}=0.0217mol(NH_4)_2CO_3 \end{gathered}[/tex]Finally, use the amounts of moles of each ion per mole of substance (determined at the beginning) to find the amount of moles of each ion present in the given volume:
[tex]\begin{gathered} 0.0217mol(NH_4)_2CO_3\cdot\frac{2molNH^+_4}{1mol(NH_4)_2CO_3}=0.0434molNH^+_4 \\ 0.0217mol(NH_4)_2CO_3\cdot\frac{1molCO^{2-}_3^{}_{}}{1mol(NH_4)_2CO_3}=0.0217molCO^{2-}_3 \end{gathered}[/tex]
