The perimeter of the rectangular playing field is 310 m.
The length is 65 meters more than the width.
Let L represents the length and W represents the width of the playing field.
[tex]L=65+W[/tex]Recall that the perimeter of a rectangular shape is given by
[tex]P=2(L+W)[/tex]Substitute the value of perimeter and length into the above formula
[tex]\begin{gathered} P=2(L+W) \\ 310=2(65+W+W) \\ 310=2(65+2W) \\ 310=130+4W \\ 310-130=4W \\ 180=4W \\ \frac{180}{4}=W \\ 45=W \\ W=45\: m \end{gathered}[/tex]So, the width is 45 m.
[tex]\begin{gathered} L=65+W \\ L=65+45 \\ L=110\: m \end{gathered}[/tex]So, the length is 110 m.