Question

a solution contains 8.68 g of glucose () and 4.78 g of ribose () in a total volume of 165.0 ml. calculate the molar concentration of each solute and the total molarity of the solution.

Answer 1

molarity of glucose  = 0.0482 / 165 X100 % = 0.029 % and that of ribose = 0.0318 / 165 = 0.018%

and the molarity of the total solution is 8%

The molar concentration can be calculated by the formula

( moles of solute/ volume of solvent multiplied by 100 ) %

moles of glucose = given mass/ molar mass

and given mass = 8.68

molar mass of glucose = 180 g

and molar mass of ribose = 150 gram

Thus mole of glucose = 8.68/ 180 = 0.0482

And molarity of glucose  = 0.0482 / 165 X100 % = 0.029 %

Thus molarity of ribose = 0.0318 / 165 = 0.018%

And molarity of the total solution = 0.08 X 100 = 8 %

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