We have
[tex]\begin{gathered} 3y-5=45 \\ y=3x-2 \end{gathered}[/tex]So we must replace the value of y of the second equation in the first equation
[tex]\begin{gathered} 3(3x-2)-5=45 \\ 9x-6-5=45 \\ 9x-6=45+5 \\ 9x-6=50 \end{gathered}[/tex]So, the answer is 9x - 6 = 50. Last option.