Given data:
The given figure of the circle.
Angle he measurement of the angle B is,
[tex]\begin{gathered} \angle B=\frac{1}{2}(180^{\circ}) \\ =90^{\circ} \end{gathered}[/tex]The measurement of the angle A is,
[tex]\begin{gathered} 2\angle A=180^{\circ}-100^{\circ} \\ \angle A=40^{\circ} \end{gathered}[/tex]In triangle ABC, the angle sum property is,
[tex]\begin{gathered} \angle A+\angle B+\angle C=180^{\circ} \\ 40^{\circ}+90^{\circ}+\angle C=180^{\circ} \\ \angle C=50^{\circ} \end{gathered}[/tex]