The density of the solution is required to convert 5% by mass acetic acid to M (molarity).
10% by mass = 10 g solution/100 g acetic acid
One mole of acetic acid in five grams (60.05 grams) equals 0.033 moles of acetic acid.
Once you are aware of the solution's density, you may determine its volume and divide the number of moles of acetic acid by the volume in liters to get M (moles/liter).
Here is how to compute the molarity if all you want to do is pretend that the density is 1 g/ml even though it is actually 1.06 g/ml.
Assuming a density of 1 g/ml, 5% by mass equals 5 g/100 g, which is the same as 5 g/100 ml.
50 g/liter x 5 g/100 milliliter
0.8 M is equal to 50 g/liter times 1 mole/60 g, or 0.83 moles/liter.
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