a 25.0 ml sample of a saturated c a ( o h ) 2 ca(oh)x2 solution is titrated with 0.030 m h c l hcl , and the equivalence point is reached after 38.1 ml of titrant are dispensed. based on this data, what is the concentration (m) of c a ( o h ) 2 ca(oh)x2 ? type answer:

A solution is a mixture in which all of the solvent has been dissolved. The bottom of the container will get covered in crystals if more solute is added.

To quantify the concentration of an identified analyte, titrations are a typical laboratory technique for quantitative chemical analysis (a substance to be analyzed). A reagent—also known as a titrant or titrator is prepared as a standard solution with known volume and concentration. The concentration of an analyte is determined by the titrant's reaction with an analyte solution, commonly known as the titrand. Titration volume is the amount of titrant that was used in the reaction with the analyte.

From the question,

We must ascertain the Ca(OH)2 solution's concentration.

Writing a balanced chemical equation for the reaction will come first.

2HCl + Ca(OH)2 CaCl2 + 2H2O is the reaction's balanced chemical equation.

This implies,

1 mole of Ca(OH)2 needs to be totally neutralized by 2 moles of HCl.

Applying the equation CaVA/CbVb = Na/Nb

Va is the volume of acid in the chemical equation for a balanced reaction.

Cb stands for base concentration.

The volume of the base is Vb.

The acid mole ratio is na.

The basic mole ratio is nb.

Ca = 0.30 m, Va = 25.0 ml, Vb = 38.1 ml, na = 1 and nb= 2 are the results from the inquiry.

Now, enter the aforementioned information into the equation CaVa/CbVb = na/nb to obtain Cb = 0.393700 M.

Hence,

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