Question

Calculate the Keq for the following reaction based on the concentrations provided 2 NO(g) + O2(g) = 2 NO2(g)[NO]= 0.50M [O2] = 0.75M [NO2] = 0.25M

Answer 1

Answer

Keq = 0.333 M⁻¹

Explanation

Chemical equation of the reaction:

2NO(g) + O₂(g) ⇄ 2NO₂(g)

Given concentrations:

[NO] = 0.50M, [O2] = 0.75M, and [NO2] = 0.25M.

The formula for Keq for the reaction is

$\text{Keq }=\frac{\lbrack NO_2\rbrack^2}{\lbrack NO_{}\rbrack^2\lbrack O_2\rbrack}^{}$

Therefore,

$\text{Keq }=\frac{0.25^2}{0.5^2\times0.75}=\frac{0.0625}{0.25\times\text{0}.75}=\frac{0.0625}{0.1875}=0.333M^{-1}$