SOLUTION:
Given: Equation of a circle describing a radio station broadcast area.
[tex]\begin{gathered} x^2+y^2=5625 \\ \text{Comparing with the general equation of a circle:} \\ (x-a)^2+(y-b)^2=r^2 \\ \text{Where (a,b) represents the centre of the circle} \\ r\text{ represents the radius of the circle} \\ \text{Therefore,} \\ The\text{ centre is the origin (0,0)} \\ \text{radius,} \\ r^2=\text{ 5625} \\ \text{Square}-\text{root both sides} \\ \sqrt[]{r^2}=\text{ }\sqrt[]{5625} \\ r=\text{ 75 miles} \end{gathered}[/tex]To find:
A) Intercepts; x-intercept, y-intercept
[tex]\begin{gathered} x-\text{intercept} \\ \text{the value of x when y=0} \\ x^2_{}+y^2=5625 \\ x^2=5625 \\ \text{square}-\text{root both sides} \\ \sqrt[]{x^2}=\text{ }\sqrt[]{5625} \\ x=\text{ 75 miles} \end{gathered}[/tex][tex]\begin{gathered} y-\text{intercept} \\ \text{the value of y when x=0} \\ x^2_{}+y^2=5625 \\ y^2=5625 \\ \text{square}-\text{root both sides} \\ \sqrt[]{y^2}=\text{ }\sqrt[]{5625} \\ y=\text{ 75 miles} \end{gathered}[/tex]B) radius
[tex]\begin{gathered} r^2=\text{ 5625} \\ \text{Square}-\text{root both sides} \\ \sqrt[]{r^2}=\text{ }\sqrt[]{5625} \\ r=\text{ 75 miles} \end{gathered}[/tex]C) Area of region
The formula for area of a circle is given as:
[tex]\begin{gathered} A=\text{ }\pi\times r^2 \\ A=\text{ }\frac{22}{7}\times75^2 \\ A=\frac{22}{7}\times5625 \\ A=\text{ 17678.57 sq miles (2 d.p)} \end{gathered}[/tex]