Question

In the accompanying diagram ABCD is a rhombus and m/EAD = 110 find m/CBF

Answer 1

Given:

Rhombus ABCD

m∠EAD = 110°

Let's find m∠CBF

In the given rhombus, we have:

m∠EAD = m∠CBA

Thus, we have:

m∠CBA = 110°

To find the m∠CBF, apply the linear pair of angles therorem:

m∠CBF + m∠CBA = 180

m∠CBF + 110 = 180

Subtract 11